Eight identical pipes can empty a full tank in half an hour. Two of the pipes are choked and cannot be used. The tank is to be emptied in 40 minutes. Determine whether the remaining pipes can empty the tank in 40 minutes.
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[tex] \frac{(8 )pipes}{(8 - 2) pipes} \times 30 \: minutes \\ \\ \frac{8}{6} \times 30 \: minutes = 40 \: minutes[/tex]
The remaining pipes can empty the tank in 40 minutes
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